Absolute average
Re: Absolute average
By "same scale" I mean set the nominal scale of both to average of nominal scales of both.
Re: Absolute average
Do you mean to set the scale of the result to the average scale of the two sources while using the original scale of each source to perform the blend, or do you mean to use the average scale of the two sources as the scale of each source in order to computer the blend?
— daan
— daan
Re: Absolute average
I do mean to use the average scale of the two sources as the scale of each source in order to computer the blend. (computer the blend? what does that mean?)
Re: Absolute average
“compute the blend” is what I intended.Piotr wrote:I do mean to use the average scale of the two sources as the scale of each source in order to computer the blend. (computer the blend? what does that mean?)
What use would this requested feature have? Instead, just set the nominal scale to be the same before blending. Or set them to you whatever you want. That gives the most flexibility with the least complication.
— daan
Re: Absolute average
Absolute average for same projections can be interesting in some situations, like averaging normal and transverse aspects.
Re: Absolute average
That was true when I wrote that. Today I discovered a method to do this. A paper is forthcoming.daan wrote:There is no known area-preserving combination of two arbitrary equal-area projections.
— daan
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Re: Absolute average
Wow, that sounds interesting!daan wrote:That was true when I wrote that. Today I discovered a method to do this. A paper is forthcoming.daan wrote:There is no known area-preserving combination of two arbitrary equal-area projections.
I’m anxious to learn about it.
Hopefully, this method will find its way into Geocart?
Kind regards,
Tobias
Re: Absolute average
Wow! That means that in the future, we may be able to combine Hammer and Smyth equal-surface and get an equal-area projection!
Re: Absolute average
Here you go.Piotr wrote:Wow! That means that in the future, we may be able to combine Hammer and Smyth equal-surface and get an equal-area projection!
I suspect, though, that there is a simpler analytic parameterization in this particular case.
— daan
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Re: Absolute average
They look like equal-area results from the generalized Wagner.
Which of course isn’t astonishing at all, given the thought that both Hammer and all cylindric equal-area projections can be obtained by the generalized Wagner.
(Although for cylindric and pseudocylindric projections, I’d rather recommend Hufnagel because it has a greater variety in the results and saves you the trouble of certain rounding errors…)
Which of course isn’t astonishing at all, given the thought that both Hammer and all cylindric equal-area projections can be obtained by the generalized Wagner.
(Although for cylindric and pseudocylindric projections, I’d rather recommend Hufnagel because it has a greater variety in the results and saves you the trouble of certain rounding errors…)